Fix the syntax in docs
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+16
-16
@@ -230,10 +230,10 @@ analysis 输入的 $1/16$ 缩放会在 inverse QMF 输出端由 $\times16$ 抵
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$$
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\begin{aligned}
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\operatorname{zone}[2k] &= \operatorname{src}[4k],\\
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\operatorname{zone}[2k+1] &= -\operatorname{src}[4k+1],\\
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\operatorname{zone}[126-2k] &= \operatorname{src}[4k+2],\\
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\operatorname{zone}[127-2k] &= \operatorname{src}[4k+3].
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\mathrm{zone}[2k] &= \mathrm{src}[4k],\\
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\mathrm{zone}[2k+1] &= -\mathrm{src}[4k+1],\\
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\mathrm{zone}[126-2k] &= \mathrm{src}[4k+2],\\
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\mathrm{zone}[127-2k] &= \mathrm{src}[4k+3].
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\end{aligned}
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$$
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@@ -242,7 +242,7 @@ $$
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$$
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F_k=
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\sum_{n=0}^{63}
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\operatorname{zone}_n
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\mathrm{zone}_n
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\exp\!\left(-j\frac{2\pi kn}{64}\right).
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$$
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@@ -277,7 +277,7 @@ $$
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$$
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y_o[64t+r]=
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\operatorname{clip}\!\left(
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\mathrm{clip}\!\left(
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16\,\mathbf y_{o,t}[r],-1,1
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\right)G_{\mathrm{clip}},
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$$
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@@ -290,7 +290,7 @@ LFE 不经过对象矩阵或 inverse QMF,而是使用 1217-sample 延迟。输
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$$
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y_{\mathrm{LFE}}[n]=
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\operatorname{clip}\!\left(
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\mathrm{clip}\!\left(
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x_{\mathrm{LFE,core}}[n-1217],-1,1
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\right).
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$$
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@@ -322,11 +322,11 @@ $$
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转换为 ADM 网格时:
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$$
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k_1=\operatorname{round}\!\left(\frac{62q_1}{32767}\right),
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k_1=\mathrm{round}\!\left(\frac{62q_1}{32767}\right),
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\quad
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k_2=\operatorname{round}\!\left(\frac{62q_2}{32767}\right),
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k_2=\mathrm{round}\!\left(\frac{62q_2}{32767}\right),
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\quad
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k_3=\operatorname{round}\!\left(\frac{15q_3}{32767}\right),
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k_3=\mathrm{round}\!\left(\frac{15q_3}{32767}\right),
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$$
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$$
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@@ -398,7 +398,7 @@ $$
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$$
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v_{\mathrm{floor}}=
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\operatorname{clamp}(2v,0,1).
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\mathrm{clamp}(2v,0,1).
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$$
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其他布局使用 $v_{\mathrm{floor}}=v$。
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@@ -441,15 +441,15 @@ $$
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前后与高度位置权重为
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$$
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p_v=\operatorname{clamp}\left(\frac v{0.6},0,1\right),
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p_v=\mathrm{clamp}\left(\frac v{0.6},0,1\right),
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$$
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$$
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p_w=\operatorname{clamp}\left(\frac{w-0.2}{0.8},0,1\right),
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p_w=\mathrm{clamp}\left(\frac{w-0.2}{0.8},0,1\right),
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$$
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$$
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p=\operatorname{clamp}(p_v+p_w,0,1).
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p=\mathrm{clamp}(p_v+p_w,0,1).
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$$
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线性补偿增益为
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@@ -550,8 +550,8 @@ $$
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$$
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y_{24}[n]=
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\operatorname{trunc}\left(
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8388607\,\operatorname{clip}(y[n],-1,1)
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\mathrm{trunc}\left(
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8388607\,\mathrm{clip}(y[n],-1,1)
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\right).
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$$
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